Where is Seymour Located? - Seymour is a city located in the Jackson County of Indiana, United States. Seymour lies between 39.0751 Degrees North latitudes and 84.4472 Degrees West longitudes.
Location Map of Seymour, Indiana
Seymour Map, Indiana, USA
Where is Seymour?: The Google Map showing the location of Seymour in the U.S. state of Indiana.
Where is Seymour Located?
Seymour is a city located in the Jackson County of Indiana, United States. Seymour lies between 39.0751 Degrees North latitudes and 84.4472 Degrees West longitudes. According to 2020 U.S.census, the population of Seymour city is 21569 people and the city has a total area of 12.14 sq mi. The city has numerous parks and recreational facilities.
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Seymour City Facts, Indiana
| City Name | Seymour |
| County | Jackson County |
| State | Indiana |
| Country | United States |
| U.S. Region | East North Central |
| Coordinates | 38.9592° N, 85.8903° W |
| Latitude | 49.3933333 |
| Longitude | -122.9444444 |
| Population (2020 Census) | 21569 |
| Population Density (Sq mi) | 1878 |
| Area (Sq mi) | 12.14 |
| Currency | US Dollar, $ (USD) |
| Time Zone | Eastern Time - UTC?05:00 (Standard), UTC?04:00 (DST) Central Time - UTC?06:00 (Standard), UTC?05:00 (DST) |
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