Where is Seymour, Indiana, USA?

Written by | Last Updated: Sept 01, 2024, 07:40 ET

Where is Seymour Located? - Seymour is a city located in the Jackson County of Indiana, United States. Seymour lies between 39.0751 Degrees North latitudes and 84.4472 Degrees West longitudes.

Location Map of Seymour, Indiana

Where is Seymour, Indiana

Seymour Map, Indiana, USA

Where is Seymour?: The Google Map showing the location of Seymour in the U.S. state of Indiana.

Where is Seymour Located?

Seymour is a city located in the Jackson County of Indiana, United States. Seymour lies between 39.0751 Degrees North latitudes and 84.4472 Degrees West longitudes. According to 2020 U.S.census, the population of Seymour city is 21569 people and the city has a total area of 12.14 sq mi. The city has numerous parks and recreational facilities.

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  • Seymour City Facts, Indiana

    City NameSeymour
    CountyJackson County
    StateIndiana
    CountryUnited States
    U.S. RegionEast North Central
    Coordinates38.9592° N, 85.8903° W
    Latitude49.3933333
    Longitude-122.9444444
    Population (2020 Census)21569
    Population Density (Sq mi)1878
    Area (Sq mi)12.14
    CurrencyUS Dollar, $ (USD)
    Time ZoneEastern Time - UTC?05:00 (Standard), UTC?04:00 (DST)
    Central Time - UTC?06:00 (Standard), UTC?05:00 (DST)

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